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Slav-nsk [51]
2 years ago
12

4.289 rounded to the nearest tenth

Mathematics
2 answers:
Novay_Z [31]2 years ago
8 0

Answer:

4.3

Step-by-step explanation:

elena-14-01-66 [18.8K]2 years ago
5 0
4.3 is your answer :)
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The quotient of ninety five and a number is what
djyliett [7]
This is how you solve it..
95/n=n
You could put 5 in and get 95/5=19.
8 0
3 years ago
10 shared between 5 students equals how many each
masha68 [24]
10 separated into 5 groups is 10/5
5 goes into 10 2 times.
10/5=2
5 0
3 years ago
Read 2 more answers
50 points and BRAINLIEST<br><br> .15m - .13m = 69.96 - 55.96
weeeeeb [17]

Answer:

m=7

Step-by-step explanation:

15m−13m=69.96−55.96

Step 1: Simplify both sides of the equation.

15m−13m=69.96−55.96

15m+−13m=69.96+−55.96

(15m+−13m)=(69.96+−55.96)(Combine Like Terms)

2m=14

2m=14

Step 2: Divide both sides by 2.

2m

2

=

14

2

5 0
3 years ago
Simplify the expression:<br> 10h2+h–6h2
cupoosta [38]

Answer:

The answer is 4h^2 + h

Step-by-step explanation:

Subtract 6h^2 from 10h^2

~Hoped this helped~

4 0
3 years ago
Read 2 more answers
Use distributive property to factor method 1. Use distributive property to expand method 2.
sasho [114]

Step-by-step explanation:

I guess method 1 means to deal with whole factors.

x + 5 = (x - 2)(x + 5)

for (x + 5) <> 0 we can divide both sides by this factor :

1 = x - 2

x = 3

for the second solution we deal with

x + 5 = 0

x = -5

so, for x = -5 and x = 3 both functions deliver the same output, and these are the intersection points.

method 2 : we multiply the expression out and solve it then

x + 5 = (x - 2)(x + 5)

x + 5 = x² + 5x - 2x - 10 = x² + 3x - 10

0 = x² + 2x - 15

the general solution to such a square equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = 2

c = -15

x = (-2 ± sqrt(2² - 4×1×-15))/(2×1) =

= (-2 ± sqrt(4 + 60))/2 = (-2 ± sqrt(64))/2 = (-2 ± 8)/2 =

= -1 ± 4

x1 = -1 + 4 = 3

x2 = -1 - 4 = -5

and you get the 2 solutions again. as expected, they are the same as with method 1, of course.

4 0
2 years ago
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