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Damm [24]
2 years ago
13

the number in this sequence increase by 40 each time. 30 70 110 115... the sequence is continued with the same rule. Which numbe

r in the sequence will be the closest to 300​
Mathematics
1 answer:
Ivahew [28]2 years ago
6 0

Answer:

315 will be the closet to 300.

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Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
A book is on sale for $6 off of the regular $24 price. What percent is the discount?
Vika [28.1K]
6/24* 100= 25%. You multiply top ( 6 and 100) and divide to bottom (600 and 24) to get 25%.
8 0
2 years ago
Read 2 more answers
Whats the distance between {-4 , 12} and {18 , 12}
belka [17]
You would need to use the distance formula.
Distance = Sqrt((x2-x1)^2+(y2-y1)^2)
Plug in your numbers
Distance = Sqrt((12+4)^2+(12-18)^2)
Distance = 17.09
4 0
3 years ago
Read 2 more answers
please help. will give brainliest! review the table of values for function p(x). what is lim (x -14) p(x), if it exists? (table
Lubov Fominskaja [6]

Answer:

DNE

Step-by-step explanation:

The the given table, we have;

As x approaches -14 from the left, at x = -14.001,  p(x) = 1.96

\lim \limits _{x \to -14^{-}} p(x) = 1.96

As x approaches -14 from the right, at x = -13.999, p(x) = 1.97

\lim \limits _{x \to -14^{+}} p(x) = 1.97

The value of p(x) when x = -14 is \lim \limits _{x \to -14} p(x) = Undefined, or is not definable, therefore, p(x) Does Not Exist (DNE) when x = -14, and we have;

\lim \limits _{x \to -14} p(x)  Does Not Exist, DNE.

3 0
3 years ago
Please help with hold page
STALIN [3.7K]
1. mucus - a slimy substance produced in the nose and throat to moisten and protect them 
2. sterile -  free from germs
3. enables - gives ability, power, or means to; makes able
4. specialize - to develop in a special way
5. critical - being important to the outcome of a situation

For #6-10, the word in italics is the one most similar to the first word.

6. scarce | plenty | many | <em>rare</em>
7. critical | <em>important</em> | useful | relaxed
8. sterile | dirty <em>| germ-free</em> | bacteria
9. enables | teaches | makes empty | <em>allows</em>
10. specialize | stretch | <em>adapt</em> | organize

I can't help you with the last one, because that's specific to you. If you have questions on how to work on that one specifically, though, feel free to message me or post a question about it. :)
4 0
2 years ago
Read 2 more answers
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