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balandron [24]
3 years ago
11

I need help with these please :) I suck at math

Mathematics
1 answer:
nikitadnepr [17]3 years ago
8 0
1)
you have similar triangles(ABC, ADE), so their side length ratios are equal

8/2=4/CE
CE*4=4
CE=1


2)
angle bisector theorem:
CD/DA=BC/BA

CD/DA=10/8
I:AD=10CD/8

we also know AC=AD+CD=6
II:CD=6-AD

insert II in I:

AD=10(6-AD)/8
=5(6-AD)/4
=(30-5AD)/4
4AD=30-5AD
9AD=30
3AD=10
AD=10/3
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Suppose f'(7)=9 and g(7)= 5. <br> Find h'(7) where h(x) = 3f(x) + 2g(x) + 7<br><br> h'(7)=???
Ratling [72]

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Step-by-step explanation:

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f'(7)=9 and g(7)= 5

We have to find : h'(7)

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⇔ h(x) = 3f(x) + 2g(x) + 7   ...equation (i)

Plugging the value of 'x' = 7 in equation (i) the equation can be re-framed as:

⇔ h(7) = 3f(7) + 2g(7) + 7

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Now plugging the value of f'=(7)=9 and g(7)=5 in the above equation:

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So the value of h=(7) = 44 .

6 0
3 years ago
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