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balandron [24]
3 years ago
11

I need help with these please :) I suck at math

Mathematics
1 answer:
nikitadnepr [17]3 years ago
8 0
1)
you have similar triangles(ABC, ADE), so their side length ratios are equal

8/2=4/CE
CE*4=4
CE=1


2)
angle bisector theorem:
CD/DA=BC/BA

CD/DA=10/8
I:AD=10CD/8

we also know AC=AD+CD=6
II:CD=6-AD

insert II in I:

AD=10(6-AD)/8
=5(6-AD)/4
=(30-5AD)/4
4AD=30-5AD
9AD=30
3AD=10
AD=10/3
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strojnjashka [21]

Answer:

4

Step-by-step explanation:

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4 0
3 years ago
If the circumference is 3/2 pi what is the area
11111nata11111 [884]

Here is your answer

\frac{9}{16} \pi \:  {units}^{2}

REASON:

Circumference(C)= 2πr

, where r is radius

Given

C= (3/2) π

So,

2\pi \: r =  \frac{3}{2}\pi

r =   \frac{\frac{3}{2}\pi}{2\pi}

r =  \frac{3}{4}

Now,

area = \pi {r}^{2}

= \pi \times  { (\frac{3}{4}) }^{2}

=  \frac{9}{16}\pi   \: {unit}^{2}

HOPE IT IS USEFUL

8 0
4 years ago
Substitution method need help for home work
Marizza181 [45]
-3y = x...so we sub in -3y for x in the other equation

-x + 7y = 70
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3y + 7y = 70
10y = 70
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y = 7

so we sub in 7 for y in either of the original equations to find x
-3y = x
-3(7) = x
-21 = x

so ur solution is (-21,7)
6 0
3 years ago
(5x + 21)° (12x + 6)
ioda
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4 years ago
Im stumped and timed.
VLD [36.1K]
I believe the answer for the second one is B ( I took this last year but I think it’s that one)
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