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Aloiza [94]
3 years ago
7

1. Write an equation of an ellipse in standard form with the center at the origin and with the given characteristics.

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
5 0

Answer:

a.

b.

d.

The answer for the entire quiz is

a.

b.

a.

d.

a.

Sergeeva-Olga [200]3 years ago
4 0

Answer:

1. A

2. B

3. A

4. D

5. A

Hope I helped!

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I REALLY NEED HELP! ive tried this so many times and just cant get it! thank you!
posledela
Like i told u earleir explain more
4 0
3 years ago
I don’t understand this problem
Paha777 [63]

Answer:

the pair of angles of SUR and NUR are complimentary so the measure of NUR  is 49 degrees. TUR is equivalent to RUQ

Step-by-step explanation:

Complimentary means they add up to 90 degrees. so 90-41= 49 so the angle measure of NUR is 90 degrees.

6 0
2 years ago
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(EASY) Is this an equilateral triangle?
Alja [10]

Answer:yes

Step-by-step explanation

4 0
2 years ago
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Find the area between the graph of the function and the x-axis over the given interval, if possible.
vodomira [7]

Answer:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

A = \int_{-\infty}^1 \frac{5}{(x-2)^2}

For this case we can use the following substitution u = x-2 and we have dx = du

A = \int_{a}^b \frac{5}{u^2} du = 5\int_{a}^b u^{-2}du

And if we solve the integral we got:

A= -\frac{5}{u} \Big|_a^b

And we can rewrite the expression again in terms of x and we got:

A = -\frac{5}{x-2} \Big|_{-\infty}^1

And we can solve this using the fundamental theorem of calculus like this:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

7 0
3 years ago
First​ estimate, and then multiply to get the exact answer. Give your answer as a whole or mixed number. 5 and two thirds times
vichka [17]
5 2/3× 3 2/5× 5= 96 1/3
3 0
2 years ago
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