Part 1) Finding x
Note the double tickmarks for segments XY and YZ. This indicates the segments are the same length, which leads to point Y being the midpoint of segment XZ.
Therefore, XZ is twice as long as XY
XZ = 2*( XY )
XZ = 2*( 2x-1 )
XZ = 4x - 2
We also know that XZ = 2(3x-4) = 6x-8. Let's equate 4x-2 and 6x-8 and solve for x
6x-8 = 4x-2
6x-4x = -2+8
2x = 6
x = 6/3
x = 3
<h3>Answer is 3</h3>
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Part 2) Finding the length of YZ
The resut of part 1 (x = 3) is plugged into the equation for XY to get
XY = 2*x-1
XY = 2*3-1
XY = 6-1
XY = 5
Segment XY is 5 units long. So is segment YZ as these two segments are the same length (aka congruent).
<h3>Answer: 5</h3>
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Part 3) Finding the length of segment XZ
The answer from the previous part was 5. This doules to 5*2 = 10
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A longer way to get the same answer is to plug x = 3 into the XZ equation and we get...
XZ = 2*(3x-4)
XZ = 2*(3*3-4)
XZ = 2*(9-4)
XZ = 2*5
XZ = 10
and we get the same answer
<h3>Answer: 10</h3>
Move constant to other side
add 1
4c^2-8c=1
divide by 4 to make leading coeficient 1
c^2-2c=1/4
take 1/2 of linear coeficient and square it
-2/2=-1, (-1)^2=1
add that to both sides
c^2-2c+1=1/4+1
factor perfect squaer and add
(c-1)^2=5/4
square root both sides
c-1=+/-(√5)/2
add 1
c=1+/-(√5)/2
c=2.12 or -0.12
Answer:
(3x^2 + 2)(x + 4).
Step-by-step explanation:
3x3 + 12x2 + 2x + 8
3x^2(x + 4) + 2(x + 4) The x + 4 is common to the 2 groups so we have:
(3x^2 + 2)(x + 4).
Answer: If I’m not mistaken, the largest area is 75 m2 and the smallest is 2 m2
Step-by-step explanation:
For both : since they are asking for the area, you should calculate the perimeter.
So for the largest area, since you know that you have 40 fences, and each are 1 meter long, and they’re also asking for the largest rectangular area, this means that only the opposite sides will have the same length, so in order to divide the rectangle with the 40 one-meter fences, the biggest sides have to be 15 meters long (so for both : 15x2=30 meters). Then you deduct from 40, 30 : 40-30 = 10 which then you can devide by 2 and find 5 + 5 and that means that the 2 smallest sides will be 5 meters long each. Then finally to calculate the perimeter you should do the biggest side multiplied by the smallest side : 15 x 5 and you find 75 m2 (squaremeters), if I’m not mistaken.
And for the smallest area you take the smallest possibilities knowing that only the opposite sides should have the same length and not all of them, so you do 1 x 2 and you find 2 m2.
Answer:
D 49.1
Step-by-step explanation:
Hope it helps
have a great day
