45 i believe it is i may be wrong!!!
Answer:
B
Step-by-step explanation:
x^3 + 2x^2 - 9x - 18 = x^2(x + 2) - 9(x + 2) = (x + 2)*(x^2 - 9)
(x + 2)/(x + 2)(x^2 - 9) = 1 / (x^2 - 9)
==============
1/(x^2 - 9) * (x^2 - 9)/(3x + 1) = 1/(3x + 1)
Yes B is correct.
Answer:
an = (1 + 2·(n - 1))/2^(n - 1) = 2^(1 - n)·(2·n - 1)
sn = 6 - 2·0.5^n·(2·n + 3)
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±
)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation: