I believe this is the question: "Quadrilateral ABCD in the figure below represents a scaled-down model of a walkway around a historic site. Quadrilateral EFGH represents the actual walkway. ABCD is similar to EFGH. Two irregular similar quadrilaterals ABCD and EFGH are drawn. AB measures 5 inches, BC measures 4 inches, CD measures 4 inches and AD measures 3 inches. EF measures 45 feet. What is the total length, in feet, of the actual walkway?"
We should determine the ratio(proportionality) of the two similar quadrilaterals. Since AB corresponds to EF, AB=5, EF=45, we know that the side lengths of EFGH is 45/5=9 times those of ABCD. The perimeter of ABCD=5+4+4+3=16 feet, so the perimeter of EFGH, the actual pathway, is 16*9=144 feet.
Answer:
(x,y)=(5,-1)
Step-by-step explanation:
1. 2x+y=9 ---> y=9-2x
2. Substitute y=9-2x into 3x-2y=17 ---> 3x-2(9-2x)=17 ---> 3x-18+4x=17 --> 7x=35 ---> x=5.
3. Substitute x=5 into 2x+y=9 ---> 2*5+y=9 ---> y=9-10 ---> y= -1
Answer:
l - y=4
m y = -2x+4
n y =x-1
p - x=-4
Step-by-step explanation:
Answer:
The lines intersect once at (2, −1).
A graphic solution to a system of equations is only as accurate as the scale of the paper or precision of the lines. At times the point of intersection will need to be estimated on the graph. When an exact solution is necessary, the system should be solved algebraically, either by substitution or by elimination.
Step-by-step explanation:
hope i helped
Answer:
<h3>The picture in the attached figure.</h3><h3> </h3><h3>we know that </h3><h3> </h3><h3>Area of the triangle is equal to </h3><h3 /><h3> A= ( b×h ) /2</h3><h3> </h3><h3>in this problem </h3>
<h3> A=47 in²</h3><h3> </h3><h3> b=x</h3><h3> </h3><h3> h=x</h3>
<h3>so </h3><h3> 47 = X * X / 2</h3>
<h3> x² = 94 </h3><h3>
</h3>
<h3> </h3><h2> Therefore</h2>
<h3> the answer is</h3>
<h3> And please follow me...</h3>
