Is it true that M is perpendicular to P?

The surface area of the prism is Square unit all measurements in the image below are in units input whole numbers only

lbvjy [14]

(8)(6)+(6)(6.5)+(10)(6.5)+(6.5)(8)=answer

6 0

2 years ago

The minimum monthly payment for anita's credit card is 2% of her balance or $10, whichever is higher. if anita's balance at the

ioda

Answer:

Step-by-step explanation:

⇒minimum payment is 2% of her balance or 10 bucks...whichever is greater...

her balance is 360

2% of 360 =

0.02(360) = 7.20

$ 10 is greater then 7.20 so ur answer is $ 10

pls mark as brainlesttttt

5 0

2 years ago

Read 2 more answers

Factor the polynomial: 6x^2 + x - 35

umka21 [38]

Answer:

= (2x+5)x(3x-7)

Step-by-step explanation:

3 0

2 years ago

In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.

WARRIOR [948]

Answer:

For First Solution: $y_1(t)=e^t$

$y_1(t)=e^t$ is the solution of equation y''-y=0.

For 2nd Solution: $y_2(t)=cosht$

$y_2(t)=cosht$ is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: $y_1(t)=e^t$

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

$y_1(t)=e^t$

First order derivative:

$y'_1(t)=e^t$

2nd order Derivative:

$y''_1(t)=e^t$

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence $y_1(t)=e^t$ is the solution of equation y''-y=0.

For 2nd Solution:

$y_2(t)=cosht$

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

$y_2(t)=cosht$

First order derivative:

$y'_2(t)=sinht$

2nd order Derivative:

$y''_2(t)=cosht$

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence $y_2(t)=cosht$ is the solution of equation y''-y=0.

3 0

3 years ago

Logarithm 2. The alkalinity of a fluid (pH) can be modeled in terms of its hydrogen ion concentration (H^+,measured in moles/lit

makkiz [27]

ok. We are given the following equation:

$ph=-\log (H)$

Where:

$\begin{gathered} P=\text{ alkalinity} \\ H=\text{ hydrogen ion concentration} \end{gathered}$

Since we are asked to determine "H" we will solve for "H" in the equation. To do that we will first multiply both sides by -1:

$-ph=\log (H)$

Now, we will use the following property of logarithms:

$\log _aB=c\rightarrow B=a^c$

Applying the property and having into account that:

$\log (H)=\log _{10}(H)$

We get:

$10^{-pH}=H$

Now we substitute the given value of "pH = 4.5":

$10^{-4.5}=H$

Solving the operation:

$0.000032=H$

Therefore, the hydrogen ion concentration of the fluid is 0.000032

7 0

9 months ago