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2 years ago

Find (fog)(x) given f(x) = 2x2-x+1 and g(x) = 4x +3

Mathematics

1 answer:

Zolol [24]2 years ago

8 0

Answer:

fg(x) = 32x²+44x+16

Step-by-step explanation:

fg(x) = f[g(x)]

= f(4x+3)

= 2(4x+3)²-(4x+3)+1

= 2(16x²+24x+9)-4x-3+1

= 32x²+44x+16

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which equation represents the function in the table?

Snowcat [4.5K]

Answer:

Step-by-step explanation:

Substitute the value of x in each function and check if it's equal to it's corresponding value of y.

Correct me if I'm wrong. I hope it helps.

8 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Yakvenalex [24]

The correct answers are :

(5x)² ≥ 46

x² + 5x ≤ 46

5x² > 46

<h3>What is Inequalities?</h3>

A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

Here, Suppose number is x

1) The square of the product of 5 and a number is not less than 46.

Step 1

Product of 5

Step 2

Square of product of 5

(5x)²

Step 3

A number is not less than 46

(5x)² ≥ 46

2) The sum of square of a number and five times that number is not more than 46

Step 1

Square of a number

x²

Step 2

Five times that number

Step 3

The sum = x² + 5x

Step 4

Is not more than 46

x² + 5x ≤ 46

3) The product of 5 and the square of a number is greater than 46

Step 1

The square of a number

x²

Step 2

The product of 5

5x²

Step 3

Is greater than 46

5x² > 46

Thus, The correct answers are :

(5x)² ≥ 46

x² + 5x ≤ 46

5x² > 46

Learn more about Inequality from:

brainly.com/question/20383699

#SPJ1

3 0

2 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

3 years ago

How to find canonical form of equation of a line then general form is given

lisabon 2012 [21]

It is a math mathematical form of objects natural stance, to find it you need the positive integer and its finite sequence of digits.

4 0

3 years ago

Help me with this please

alina1380 [7]

If you assign variables to the problem, it can make things a lot simpler. Lets say chairs are x and tables are y. Therefore you have:
2x+6y=40
5x+3y=25
Now you can isolate the variable of one equation and put it into another (it doesn't matter which. I'm going to manipulate the top equation to plug into the bottom one).
2x=40-6y
x=20-3y
Now I plug into bottom equatioin:
5(20-3y) + 3y=25
100-15y+3y=25
100-12y=25
-12y=-75
y=$6.25
Now you can plug in y in either equation to get x.
2x+6(6.25)=40
37.5+2x=40
2x=2.5
x=1.25
So it costs $6.25 for each table and $1.25 for each chair. If you think about it, it would make sense for the table to cost more for the chair.

6 0

4 years ago