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jeka57 [31]
2 years ago
11

How to find canonical form of equation of a line then general form is given

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
4 0
It is a math mathematical form of objects natural stance, to find it you need the positive integer and its finite sequence of digits.
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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Statistics when mode is best measure of central tendency.
ehidna [41]

Answer:

The mode is the least used of the measures of central tendency

Step-by-step explanation:

6 0
2 years ago
Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north. At wha
Fiesta28 [93]

I've attached an image showing the coordinates of Ship A and Ship B.

Answer:

distressed vessel is located at (1, 1.5)

Step-by-step explanation:

From the image attached, we can see that;

Coordinate of ship A is (3, 4)

Coordinate of ship B is (1, 1)

Now, we are told that Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north.

This means that the distressed ship is somewhere in between ship A & B.

To solve this, we will extend the arrow line from Ship A in that same SW direction and we will do the same for ship B in the same North direction. Their point of intersection is where the distressed ship is located.

Now, if we do that, we will see that they will intersect at the point; (1, 1.5)

Thus,distressed vessel is located at (1, 1.5)

5 0
3 years ago
Find the distance between the points (5,0) and (-5,3)
oksano4ka [1.4K]

Answer:

10.4

Step-by-step explanation:

√(5--5)²+(0-3)²

√100+9

√109=10.4

4 0
2 years ago
Write a rule for the nth term of the arithmetic sequence described below.
belka [17]

Answer:

an = 115 + (n - 1) (-6)

a25 = - 29

Step-by-step explanation:

We use the definition for the nth term of an arithmetic sequence:

an = a1 + (n - 1) d

a5 = 91 = a1 + (5 - 1) d

91 = a1 + 4 d

a20 = 1 = a1 + (20 - 1) d = a1 + 19 d

1 = a1 + 19 d

now we subtract term by term one expression from the other

90 = 4 d - 19 d

90 = - 15 d

divide both sides by -15 to isolate d

d = 90 / (-15) = -6

Now we can calculate what a1 is using for example:

1 = a1 + 19 d

1 = a1 - 114

add 114 to both sides:

115 = a1

Then our general expression for the sequence is:

an = 115 + (n - 1) (-6)

We can now use it to calculate the value of a25:

a25 = 115 + (24) * (-6) = -29

7 0
2 years ago
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