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sergij07 [2.7K]
2 years ago
9

Solve the linear equations below by using:

Mathematics
1 answer:
bija089 [108]2 years ago
4 0
A. Y= -7
X=2
4x+2y=-6
+(3x-2y=-8
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3 kg of potatoes and 2 kg of apples cost a total of £7.33.
KengaRu [80]

Answer:

€2.24

Step-by-step explanation:

Let, the potatoes be x and apples be y

A/c to question,

4x = 3.80

x = 0.95

And,

3x + 2y = 7.33

3*0.95 + 2y = 7.33

2y = 7.33 - 2.85

y = 4.48/2

y = €2.24

Hence, the cost of 1 kg apple (y) = €2.24

8 0
2 years ago
What is the value of x?
Blizzard [7]

check the picture below.

so, when we have a line from a 90° angle running perpendicular to the opposite side, like in this case, we end up with three similar triangles, a large one containing the other two, a medium and a small one.

now, using the sides proportions as you see there, of the small and large one, we get that much.

3 0
3 years ago
How do I do this question folks?
horsena [70]

Answer:

Correct answer: B

Step-by-step explanation:

Syntax: in piecewise functions such as the one attached, the "if:" section shows the domain, or x-axis values which that function pertains to.

In the graph, you can see that the graph is defined for -3\leq x < 1 (not-including 1 because there is an open hole there, indicating it is not part of the domain), and 2\leq x\leq 4.

Now that we know the domain, we can attach it to the graphs that lie on those domains.

We see that the leftmost line appears to have a positive slope and a negative y-intercept, and that the second line should have a positive y-intercept and a negative slope.

At this point, you can just start crossing off answers that don't meet this criteria.

Cheers!!

7 0
3 years ago
Joseph drives 125 miles in 2 and 1/2 hours. At the same rate,how far will he be able to travel in 6 hours
pshichka [43]
300 miles You would do 125/2.5= 50 Then you a would do 50*6=300
3 0
3 years ago
If you can’t see the answer choices , they are <br> A. 9<br> B. 8 <br> C. 10 <br> D. 12
ANTONII [103]

Answer:a)9

I think

Step-by-step explanation:

6 0
2 years ago
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