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Otrada [13]
3 years ago
14

Plz help me get the right answer to these ASAP

Mathematics
2 answers:
Kryger [21]3 years ago
7 0

Hi!

\frac{1}{2} c > -1\\c > -2\\

Hope this helps!

RoseWind [281]3 years ago
6 0

Answer:

<h2>c > -2</h2>

Step-by-step explanation:

\dfrac{1}{2}c>-1\qquad\text{multiply both sides by 2}\\\\2\!\!\!\!\diagup^1\cdot\dfrac{1}{2\!\!\!\!\diagup_1}c>(2)(-1)\\\\c>-2

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Hitman42 [59]
-4r-24=-63
-4r=-63+24
4r=39
r=9, 75
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3 0
3 years ago
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Dennis and Ivy share some sweets between them in the ratio 7:4 Dennis got 42 sweets. How many does ivy get
MrRa [10]

Answer:

Ivy = 24

Step-by-step explanation:

Given

Dennis : Ivy = 7 : 4

Required

Determine the amount of sweet Ivy gets when Dennis = 42

We have:

Dennis : Ivy = 7 : 4 and

Dennis = 42

Substitute 42 for Dennis in Dennis : Ivy = 7 : 4

42 : Ivy = 7 : 4

Convert to fraction

\frac{42}{Ivy} = \frac{7}{4}

Cross Multiply:

Ivy * 7 = 42 * 4

Divide through by 7

\frac{Ivy * 7}{7} = \frac{42 * 4}{7}

Ivy = \frac{42 * 4}{7}

Ivy = 6* 4

Ivy = 24

6 0
3 years ago
Will give brainlyest if u help
goblinko [34]

Answer:

No, because it fails the vertical line test ⇒ B

Step-by-step explanation:

To check if the graph represents a function or not, use the vertical line test

<em>Vertical line test:</em> <em>Draw a vertical line to cuts the graph in different positions, </em>

  • <em>if the line cuts the graph at just </em><em>one point in all positions</em><em>, then the graph </em><em>represents a function</em>
  • <em>if the line cuts the graph at </em><em>more than one point</em><em> </em><em>in any position</em><em>, then the graph </em><em>does not represent a function </em>

In the given figure

→ Draw vertical line passes through points 2, 6, 7 to cuts the graph

∵ The vertical line at x = 2 cuts the graph at two points

∵ The vertical line at x = 6 cuts the graph at two points

∵ The vertical line at x = 7 cuts the graph at one point

→ That means the vertical line cuts the graph at more than 1 point

   in some positions

∴ The graph does not represent a function because it fails the vertical

   line test

7 0
3 years ago
Determine whether The given segments have the same length. Justify your answer
Semenov [28]

We know the distance formula is

\sqrt{ (x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 }

9)

Here A( -4,2) and B(1,4)

So length of AB

= \sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29}

Also C(2,1)

Length of BC

= \sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26}

So we can see that length of AB is not equal to length of BC

11.

Now AB = \sqrt{29}

Also C(2,-1) & D(4,4)

Length of CD

= \sqrt{(4-2)^2+(4-(-1)) ^2} =\sqrt{2^2+5^2} =\sqrt{29}

Yes AB = CD

5 0
3 years ago
What is the prime factorization of 108
Anika [276]

☆What is the prime factorization of 108?

To find the prime factorization, first divide 108 by 2.

108 \div 2 = 54

You have 2 numbers: 54 and 2. 2 is a prime number and 54 isn't. Divide 54 by 2 until every factor of 54 is prime.

★ Prime number collection: 2

54 \div 2 = 27

Add 2 to the "prime number collection". Divide 27 by factors until every factor you find is prime.

★ Prime number collection: 2, 2

27 \div 3 = 9

Add 3 to the "prime number collection". Divide 9 by a factor of it to find more prime numbers.

★ Prime number collection: 2, 2, 3

9 \div 3 = 3

The two 3's are prime. No more dividing! Add those to the "prime number collection".

★ Prime number collection: 2, 2, 3, 3, 3

Multiply all the numbers in your "prime number collection".

2 \times 2 \times 3 \times 3 \times 3

6 0
4 years ago
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