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2 years ago

Help me!!! solve the inequality!! 8 ≤ x < 6

Mathematics

1 answer:

choli [55]2 years ago

4 0

Hello! the answer to this inequality is no solutions, since there are no values of x for which this can be true.

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a triangle has one side that is 4cm long and one that is 9cm long the third side is a whole number of cm. what is the shortest p

Alla [95]

Answer:

Step-by-step explanation:

Since it must be an integer, 5 would make it up to the full length of the longest line. What you get is not quite a triangle. The way to get a triangle is to add one more to the 5 to make 6

Answer: 6 cm

4 0

1 year ago

Solve the equation to get the value y

tia_tia [17]

Answer:

y=11

x=-4

Step-by-step explanation:

y =-x+7

2x-5y=-7

insert the first equation into the second like so...

2x+5x-35=-7

Now rearrange...

2x+5x=-7+35

Now solve...

7x=-28

x=-4

Now incert x in any equation...

y=4+7

y=11

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2 years ago

Read 2 more answers

Ben has a bag with 4 green counters 4 red counters and 12 white counters Ben takes a counter from the bag at random find the pro

zvonat [6]

I’m not getting the question??

8 0

1 year ago

Inquiries arrive at a record message device according to a Poisson process of rate 15 inquiries per minute. The probability that

zloy xaker [14]

Answer:

0.0498 = 4.98%

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Inquiries arrive at a record message device according to a Poisson process of rate 15 inquiries per minute.

Each minute has 60 seconds.

So a rate of 1 inquire each 4 seconds.

The probability that it takes more than 12 seconds for the first inquiry to arrive is approximately

Mean of 1 inquire each 4 seconds, so for 12 seconds $\mu = \frac{12}{4} = 3$

This probability is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

5 0

2 years ago

Simplify x^2 + (y - 4)^2

Troyanec [42]

X^2 + y^2 - 8y + 16 :)

6 0

3 years ago