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Montano1993 [528]
3 years ago
13

In 1992, Jason bought a gallon of gas for $1.18. Yesterday, he bought a gallon of gas for $2.10. What is the percentage increase

of the price of a gallon of gas
from 1992 to yesterday? If necessary, round to the nearest tenth of a percent.
Mathematics
1 answer:
IceJOKER [234]3 years ago
6 0

Answer:

1.77 percent increase

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Which statement best describes the area of Triangle ABC shown below?
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1. Write an equation in point-slope form of the line that that passes through the point (4,-5) and has a
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Answer:

y + 5 = (3/2)(x - 4)

Step-by-step explanation:

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The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers
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Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

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Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

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Answer:

52.75 miles per hour (MPH)

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422÷8 is equal to 52.75

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