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2 years ago

Order 130 inches, 4 yards, 10 feet from greatest to least

Mathematics

2 answers:

PtichkaEL [24]2 years ago

5 0

Answer:

Step-by-step explanation:

Before comparison can take place, these three measurements must be expressed in the same unit of measurement:

130 inches becomes 130/12 feet, or 10.83 ft;

4 yards becomes 4*3 feet, or 12 feet; qne

10 feet stays as is.

It becomes obvious that the greatest measurement is 12 feet, followed by 10.83 feet, followed by 10 feet.

Volgvan2 years ago

5 0

Answer:

4 yards, 130 inches, 10 feet

Step-by-step explanation:

i put all amounts into inches

4 yards= 144 inches

10 feet=120 inches

by putting all numbers into the same units you can correctly order them without messing up proportions :))

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3 years ago

Read 2 more answers

16 divided by 1 and 7/9

stellarik [79]

Answer:

Alright well the Answer to this question is

9 Hope this helps :)

Step 1: Convert to mixed number 1 7/9 into an improper fraction first by multiplying the denominator, by the whole number

Step 2: Then add the numerator, to get the new numerator. Place the New numerator over the old denominator

16 divided by 16 and 9

To divide by fraction, multiply by it's reciprocal 16(9/16)

Cancel the common factor of 16, then simplify 1/1 9/1 which gives u

9 Hope all this helps :)

Step-by-step explanation:

8 0

3 years ago

Suppose a randomly generated list of numbers from 0 to 9 that has a probability success of 80%. which of these groups of numbers

maria [59]

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3 years ago

Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a

Mashutka [201]

Answer:

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

Step-by-step explanation:

Given

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Required

Make the denominator equal

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Factorize the denominator

$\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}$

$\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}$

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

$\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}$

$\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}$

$\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}$

<em>The expression now have the same denominator</em>

7 0

3 years ago