probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
X=3
Just look at where the two lines intercept and see the x value
The answer is C 41 because those two numbers are in the middle when arranging them
<span>Analogicaly as in the previous question - firstly let's find the common denominator for those fractions:
2/3 = 12/18
2/9 = 4/18
5/6 = 15/18
11/18 = 11/18 :)
From the least to the greatest:
2/9, 11/18, 2/3, 5/6</span>
