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2 years ago

Why 10^33/2=5*10^32? Explain, pls. :(

Mathematics

1 answer:

german2 years ago

4 0

Answer:

see below

Step-by-step explanation:

10^33/2

Rewriting the numerator as 10 * 10 ^ 32

10 * 10 ^32

--------------------

10/2 = 5

5 * 10 ^32

Therefore

10^33/2=5*10^32

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Ivenika [448]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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I need help bruv. For the function y=x^2 - 5x - 6 .

lara [203]

Answer:

a. Vertex = (2.5,-12.25)

b. y-intercept = (0,-6)

c. x-intercept = (6,0) ; (-1,0)

Step-by-step explanation:

Your equation is written as:

$y = ax^{2} + bx +c$

The easiest way to find the vertex is writing the equation this way:

$y = a(x-h)^{2}+k$

Being the vertex (h,k)

So first complete the square

$y = x^{2} -5x -6 \\y = x^{2} - 2(2.5x) -6 \\y = x^{2} - 2(2.5x) +2.5^{2} - 2.5^{2} -6 \\y = (x^{2} -2(2.5x) + 2.5^{2}) -6.25 - 6 \\y = (x-2.5)^{2} -12.25$

Vertex : (2.5,-12.25)

To find the y-intercept you need to replace the equation when x = 0 and get y

$y = (0)^{2} - 5(0) -6\\y = - 6$

To find the x-intercept you need to replace the equation when y = 0 and get x

$0 = x^{2} - 5x -6 \\0 = (x-6)(x+1)\\x = 6\\x = -1$

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3 years ago

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3 years ago

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Y-3=5(x-2) what are the intercepts t of x and y x=(_,_) y=(_,_)

yan [13]

$The\ x\ intercept\ is\ (\frac{7}{5}, 0)$

The y intercept is (0, -7)

Solution:

Given equation is:

y - 3 = 5(x - 2)

Find the x intercept

Substitute y = 0 in given equation

$0-3=5(x-2)\\\\-3=5x - 10\\\\5x = -3 + 10\\\\5x = 7\\\\x = \frac{7}{5}\\\\Thus\ the\ x\ intercept\ is\ (\frac{7}{5}, 0)$

Find the y intercept:

Substitute x = 0 in given equation

$y - 3 = 5(0-2)\\\\y - 3 = -10\\\\y = -10 + 3\\\\y = -7$

Thus the y intercept is (0, -7)

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3 years ago