Answer:
No
Step-by-step explanation:
Given values are
f(x) = 5x^3+60x^2+109x+90
x = -10.
Given Polynomial is 5x^3+60x^2+109x+90 .
= (90)+(5.x^3)+(60.x^2)+(109.x)
By putting x = (-10) we can rewrite it as
= (90)+(5.(-10)^3)+(60.(-10)^2)+(109.(-10))
= (90)+(-5000)+(6000)+(-1090)
= 0
The remainder of given polynomial is 0.
If x is fish, y is octopi, and z is crabs, then you would have to know the numbers.
Then your answer would be c. 30x+80y-15z.
Because x=+30, y=+80, and z=-15.
I hope that helps. If you need any further help on this problem just ask.
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
Answer:
22%
Step-by-step explanation:
Answer:
option D. 4.7 x 10-4 m
Step-by-step explanation:
<u><em>The correct question is</em></u>
• cell P: 5.0 x 10-4 meters
• cell Q: 3.0 x 10-5 meters
we have
The diameter of cell P is 
The diameter of cell Q is 
Rewrite the diameter of cell P as
Find the difference
Rewrite the difference as
