Answer:x=7
Step-by-step explanation:
Here AD=6
AB=6 (tangents drawn from external point to a circle are equal)
Then BC=13-6=7
Now, CE=BC=7(tangents drawn from external point to a circle are equal)
EF=14-7=7
EF=FG=x=7(tangents drawn from external point to a circle are equal)
The three consecutive integers are: x, (x+1) and (x+2).
We can suggest this equation:
x+(x+1)+(x+2)=126
3x+3=126
3x=126-3
3x=123
x=123/3
x=41
x=41
(x+1)=41+1=42
(x+2)=41+2=43
Answer: the three consecutive integers would be: 41,42 and 43.
Answer:
-11
Step-by-step explanation:
X + 8 = -3
x = -11
11-8
3
-11 - 8 = -3
Base in your question the coordinate is P is 2, PQ has a coordinate of 8 while PR has a coordinate of 12. To find the mid point of each segment you must first find the coordinate of QR which is from 8-12. So the answer will be
PQ = 5, PR = 6, and QR= 10
