The answer to the question
Answer:
The volume of a rectangular prism is simply the product of its three dimensions: in your case, the volume of the prism is, given
x
,
(
x
+
6
)
(
x
−
2
)
(
x
−
1
)
.
A polynomial is a sum (with some coefficients) of powers of
x
, so, if we expand the product just written, we have
(
(
x
+
6
)
(
x
−
2
)
)
(
x
−
1
)
=
(
x
2
−
2
x
+
6
x
−
12
)
(
x
−
1
)
=
(
x
2
+
4
x
−
12
)
(
x
−
1
)
=
x
3
+
4
x
2
−
12
x
−
x
2
−
4
x
+
12
=
x
3
+
3
x
2
−
16
x
+
12
Which is a polynomial, and expresses the volume of the prism
Step-by-step explanation:
The volume of a rectangular prism is simply the product of its three dimensions: in your case, the volume of the prism is, given
x
,
(
x
+
6
)
(
x
−
2
)
(
x
−
1
)
.
A polynomial is a sum (with some coefficients) of powers of
x
, so, if we expand the product just written, we have
(
(
x
+
6
)
(
x
−
2
)
)
(
x
−
1
)
=
(
x
2
−
2
x
+
6
x
−
12
)
(
x
−
1
)
=
(
x
2
+
4
x
−
12
)
(
x
−
1
)
=
x
3
+
4
x
2
−
12
x
−
x
2
−
4
x
+
12
=
x
3
+
3
x
2
−
16
x
+
12
Which is a polynomial, and expresses the volume of the prism
<span>8x + 10 - 5x = 15
3x + 10 = 15
3x = 5
x = 5/3
hope it helps</span>
The inverse of the statement is M be the point on PQ since PM is congruent to QM than M is midpoint on the PQ.
<h3>What do you mean by inverse?</h3>
Inverse of the statement means that explain the condition in reverse way or vice versa.
Since, M is the midpoint of PQ, then PM is congruent to QM.
Proving in reverse way, let m be the point between P and Q the distance M from P is equal to the distance from M to Q. Which implies that M lies as the mid of the P and Q.
Thus, the inverse of the statement is M be the point on PQ since PM is congruent to QM than M is midpoint on the PQ.
Learn more about inverse here:
brainly.com/question/5338106
#SPJ1
Answer: d. (17, 20)
Step-by-step explanation:
We have the following system of equations:
(1)
(2)
Isolating 
from (1):
(3)
Substituting (3) in (2):
(4)
Isolating 
:
(5)
(6)
(7)
Substituting (7) in (1):
(8)
Isolating :
(9)
Hence, the correct option is d. (17, 20)
