Answer:
8√3
Step-by-step explanation:
Let a, b = the positive numbers, and the sum = s,
(1)---- ab = 192
(2)--- a + b = s
Since we want to find the minimum sum, we'll have to substitute one of the variables (either a or b) from (1) to (2), I'll choose b,
From (1), b = 192/a
Substitute b = 192/a into (2),
s = a + 192/a
Now, we are able to use a concept of calculus (maximum & minimum) to solve it, just remember 2 steps in finding the values of x in maxima minima question:
1) find dy/dx
2) Find x from dy/dx = 0
ds/da = 1 - 192/a²
When ds/da = 0,
1 - 192/a² = 0
a² = 192
a = ±√192
a = 8√3 , -8√3
Since a is positive, a = 8√3
Substitute a into (1),
b = 192/(8√3)
b = 8√3
Therefore, the two positive numbers are 8√3... and 8√3
