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Leya [2.2K]
3 years ago
8

ecn 221 The sodium content of a popular sports drink is listed as 206 mg in a 32-oz bottle. Analysis of 14 bottles indicates a s

ample mean of 217.5 mg with a sample standard deviation of 14.9 mg. (a) State the hypotheses for a two-tailed test of the claimed sodium content.
Mathematics
1 answer:
spayn [35]3 years ago
3 0

Answer:

H_{0}: \mu = 206\text{ mg}\\H_A: \mu \neq 206\text{ mg}

Step-by-step explanation:

We are given the following in the question:

Population mean, μ =  206 mg

Sample mean, \bar{x} = 217.5 mg

Sample size, n = 14

Sample standard deviation, s = 14.9 mg

Claim:

The mean sodium content for the sports drink is not 206 mg. It is different than 206 mg.

Thus, we design the null and the alternate hypothesis

H_{0}: \mu = 206\text{ mg}\\H_A: \mu \neq 206\text{ mg}

We use two-tailed t test to perform this hypothesis.

     

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Answer:   -2, which is choice C

Work Shown:

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The slope is -2

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The expressions which are equivalent to 6¹⁶ are

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<h3>Equivalent expressions </h3>

From the question, we are to determine which of the given expressions are equivalent to 6¹⁶

From one of the laws of indices, we have that

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Then,

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Hence, the expressions which are equivalent to 6¹⁶ are

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and (6^{-4}) ^{\times -4}

Learn more on Equivalent expressions here: brainly.com/question/21643960

#SPJ1

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How do I do this problem
Elanso [62]
That the first question

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