Answer:
0.55555555
Step-by-step explanation:
You would basically go back and trace all your steps, that's what I do. And if your answer seems reasonable then you have the right answer but if your work doesn't match the answer than you've messed up.
I hope I helped if I did like my answer and comment down below thx
we have 4 gals, Stephanie, Andrea, Emily and Becca.
btw the end point should be (-6, -7) and the start point is (8, 6).
so, if we know the distance between those two points, we can just cut it in 4 equal pieces and each gal will be driving a piece.
now, Emily's turn is after Andrea, BUT, we had first Stephenie driving ¼ of the way, then Andrea driving ¼ of the way too, but after ¼+¼, Emily comes on, but ¼+¼ is really 1/2, so when Emily starts, is really half-way through, or the midpoint of that distance.

Emily's turn ends ¼ of the way later, which will be pretty much half-way in between (1, -½) and (-6, -7), so is really the midpoint of those two.

If the discriminant(b^2-4ac) is rational, then the quadratic is rational.
~ThePirc
<span><span>let x = cows last year
</span>
</span><span><span>let y = bulls last year
</span>
</span><span><span>x + y = last years total
</span>
</span><span><span>0.9x + 1.5y = 660 (this year's total)
</span>
<span>1.1(x+y) = 660 </span>= </span><span>1.1x + 1.1y = 660
</span><span>
</span><span><span>so:
</span>
</span><span><span>0.9x + 1.5y = 1.1x + 1.1y
</span>
</span><span><span>subtract 0.9x from each side:
</span>
</span><span><span>1.5y = 0.2x + 1.1y
</span>
</span><span><span>subtract 1.1y from each side
</span>
</span><span><span>0.4y = 0.2x
</span>
</span><span><span>to make x 1 multiply both sides by 5
</span>
</span><span><span>2y = x
</span>
</span><span><span>substitute for x in one of the original problems:
</span>
since they had 660 this year and that number is 10%
higher than last year, then we had 600 total last year. </span>
<span><span>So:
</span>
</span><span><span>600 = x + y
</span>
</span><span><span>substitute into that one with the 2y = x
</span>
</span><span><span>600 = 2y + y
</span>
</span><span><span>600 = 3y
</span>
</span><span><span>200 = y
</span>
</span><span><span>then 600 - y = x
</span>
</span><span><span>so 600 - 200 = x
</span>
400 = x</span>
<span> So you had 400 cows and 200 bulls last year</span>