Answer:
i think its C
Step-by-step explanation:
Answer:
35°
Step-by-step explanation:
Inscribed angle s is half the measure of the arc it subtends. That arc is the supplement to the 110° arc shown. The arc is 70°, so angle s is 35°.
Answer:
From your question, I am assuming you are talking about an absolute value graph. In this case the answer would be y = |2 + 6|
Step-by-step explanation: Always remember, when you are graphing absolute value graphs:
When you shift left or right, you put the amount you are shifting inside the absolute value sign.
When you are shifting up or down, you put the amount you are shifting outside the absolute value sign.
When shifting left on a graph, you usually think of subtraction. However, when dealing with absolute value graphs, when you are shifting left, you use addition, as you can see in this problem.
The same goes for right. You use subtraction when shifting right, contrary to what you may think.
However, when you go up, you still use addition, and when you shift down, you still use subtraction.
Answer: 8√3
<u>Step-by-step explanation:</u>
ΔXVW is a 30°-60°-90° triangle. This special triangle has corresponding sides of lengths: b - b√3 - 2b. So,
VW = b
XW = b√3
XV = 2b
Since, YV = 24, then XW = 24 and we stated above that XW = b√3. So,
24 = b√3

= b
= b
= b
8√3 = b
We are looking for side YX which is congruent (equal) to VW and we stated above that VW = b, So, VW = 8√3
Answer:
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
Step-by-step explanation:
Sample size, n = 51
p = 0.62
1 - p = 1 - 0.62 = 0.38
n = 515
Confidence level = 90% = Zcritical at 90% = 1.645
Confidence interval = (p ± margin of error)
Margin of Error = Zcritical * sqrt[(p(1-p))/n]
Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]
Margin of Error = 1.645 * 0.0214
Margin of Error = 0.035203
Lower boundary = (0.62 - 0.035203) = 0.584797
Upper boundary = (0.62 + 0.035203) = 0.655203
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.