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Anit [1.1K]
3 years ago
14

How are repeating decimals used in real-world situations

Mathematics
2 answers:
g100num [7]3 years ago
7 0

Answer:

Repeated decimals are used in real-world situations such as calculating volumes of cones and spheres

Step-by-step explanation:

we know that

A <u>repeating decimal</u> is a decimal in which after a certain point a particular digit or sequence of digits repeats itself indefinitely.

Example A

The number \frac{1}{3} is a repeating decimal because

\frac{1}{3}=0.3333...

The number \frac{1}{3} is used in real world situation to calculate the volume of a cone

V=\frac{1}{3}\pi r^{2} h

Example B

The number \frac{4}{3} is a repeating decimal because

\frac{4}{3}=1.3333...

The number \frac{4}{3} is used in real world situation to calculate the volume of a sphere

V=\frac{4}{3}\pi r^{3}

kumpel [21]3 years ago
4 0
Amount of money and checks could be one...
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nika2105 [10]
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8 0
3 years ago
Six less than a number is twenty
nignag [31]

Answer:

the start numbew woould be 26

Step-by-step explanation:

6 less than 26 is 20

6 0
2 years ago
Read 2 more answers
HELP ON A TEST
sergejj [24]

Answer:

(-1, 6)

Step-by-step explanation:

The midpoint of a line segment is effectively the point that lies halfway between two pairs of coordinates on a line. The coordinates we're concerned with here are (-4, 10) and (2, 2). So first think about what is halfway between -4 and 2 (or you can add -4 and 2 then divide by 2) and do the same with 10 and 2. This will give you (-1, 6).

5 0
2 years ago
Write a quadratic relation in the form y = ax2 + bx + c with roots 4 and - 3 and
pochemuha

Answer:

y =  2*x^2 - 2*x - 24

Step-by-step explanation:

If we have a quadratic function with roots a and b, we can write the equation for that function as:

y = f(x) = A*(x - a)*(x - b)

Where A is the leading coefficient.

In this case, we know that the roots are: 4 and -3

Then the function will be something like:

f(x) = A*(x - 4)*(x - (-3) )

f(x) = A*(x - 4)*(x + 3)

Now we need to determine the value of A.

We also know that the graph of the function passes through the point (3, -12)

This means that:

f(3) = -12

Then:

-12 = A*(3 - 4)*(3 + 3)

-12 = A*(-1)*(6)

-12 = A*(-6)

-12/-6 = A

2 = A

Then the equation is:

y = f(x) = 2*(x - 4)*(x + 3)

Now we need to write this in standard form, so we just need to expand the equation:

y = f(x) = 2*(x^2 + x*3 - x*4 - 4*3)

y = f(x) = 2*(x^2 - x - 12)

y = f(x) = 2*x^2 - 2*x - 24

Then the relation is:

y =  2*x^2 - 2*x - 24

4 0
3 years ago
34.7985347985 rounded to the nearest tenth
Nina [5.8K]
The answer would be 34.8 I’m pretty sure
7 0
2 years ago
Read 2 more answers
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