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3 years ago

I need help on this, picture is attached below

Mathematics

1 answer:

Paladinen [302]3 years ago

4 0

<h3>Answer: 37 degrees</h3>

=====================================

Explanation:

Refer to the diagram below. I've marked angles FBD and ECG in red. We can see that they are alternate exterior angles because they are

Outside (aka exterior) of the parallel lines

On alternating sides of the transversal cut

Because JD is parallel to EK, this means the alternate exterior angles are congruent. Therefore, angle ECG is also 37 degrees.

Ignore angle ABG and ignore line AH. In my opinion, this is filler added as a distraction.

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The area of a triangle is 8.50 square inches . The triangles height is 15inches . What is the length of the base?A) 6 inches b)

DochEvi [55]

Answer:

I think you mistyped the question

Step-by-step explanation:

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3 years ago

2x2 – 9x + 2 = –1

Reika [66]

Answer:

C) The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

<u>Discriminant</u>

$b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0$

$\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}$

$\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}$

$\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}$

$2x^2-9x+2=-1$

$\implies 2x^2-9x+3=0$

$\implies a=2, b=-9, c=3$

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2 years ago

3x^2 - 4x = -2<br> Solve

amid [387]

Answer:

$x = \bigg \{\frac{ 2 - \sqrt{2} \: i }{3}, \: \: \frac{ 2 + \sqrt{2} \: i }{3} \bigg \}$

Step-by-step explanation:

$3 {x}^{2} - 4x = - 2 \\ 3 {x}^{2} - 4x + 2 = 0 \\ equating \: it \: with \\ a {x}^{2} + bx + c = 0 \\ a = 3 \: \: b = - 4 \: \: c = 2 \\ {b}^{2} - 4ac \\ = {( - 4)}^{2} - 4 \times 3 \times 2 \\ = 16 - 24 \\ = - 8 \\ \ {b}^{2} - 4ac < 0 \\ \therefore \: given \: quadratic \: equation \: have \: \\ imaginary \: solutios. \\ \\ x = \frac{ - b \pm \sqrt{{b}^{2} - 4ac } }{2a} \\ = \frac{ - ( - 4) \pm \sqrt{ - 8} }{2 \times 3} \\ = \frac{ 4 \pm 2\sqrt{2} \: i }{2 \times 3} \\ = \frac{ 2 \pm \sqrt{2} \: i }{3} \\ \therefore \: x = \frac{ 2 - \sqrt{2} \: i }{3} \: or \: x = \frac{ 2 + \sqrt{2} \: i }{3} \: \\ \\ x = \bigg \{\frac{ 2 - \sqrt{2} \: i }{3}, \: \: \frac{ 2 + \sqrt{2} \: i }{3} \bigg \}$

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3 years ago

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Sure, tell me about yourself before though

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2 years ago

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5 - 3 9/16 - setup
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3 years ago