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Mars2501 [29]
3 years ago
5

Choose the imensions that represen this rectlangl

Mathematics
1 answer:
almond37 [142]3 years ago
3 0

Answer:B

Step-by-step explanation:I hope it help

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Samantha is making some floral arrangements.The table shows the prices for packs of six of each type of flower.
belka [17]
Okay so the first thing we should do here is round 5.29 rounds to 5.30 3.59 rounds to 3.60 and 4.79 rounds to 4.80 now add all of those up youll get 13.7 you can round that to 14 so samanthas estimate is accurate
4 0
3 years ago
Please help quick homework due in 30 min
Step2247 [10]

Answer:

D

Step-by-step explanation:

Pretty sure it's correct

3 0
3 years ago
Read 2 more answers
Find the value of y. Round your answers to the nearest tenth
ANTONII [103]

Answer:

y ≈ 4.3

Step-by-step explanation:

Since the figures are similar then the ratios of corresponding sides are equal, that is

\frac{AB}{RS} = \frac{ED}{VU} , substitute values

\frac{6}{4} = \frac{8}{y+1} ( cross- multiply )

6(y + 1) = 32

6y + 6 = 32 ( subtract 6 from both sides )

6y = 26 ( divide both sides by 6 )

y ≈ 4.3 ( to the nearest tenth )

4 0
3 years ago
Read 2 more answers
(a) A newspaper conducted a statewide survey concerning the 1998 race for state senator. The newspaper took a SRS of 1200 regist
Sladkaya [172]

Answer:

n=9604

Step-by-step explanation:

1) Notation and definitions

X=620 number of people that would vote for the Republican candidate

n=1200 random sample taken

\hat p=\frac{620}{1200}=0.517 estimated proportion of people that would vote for the Republican candidate

p true population proportion of people that would vote for the Republican candidate

Me= 0.01 represent th margin of error.

Confidence =0.95 or 95%

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1- p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

The problem says that we need to use \hat p =0.05, and replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.96})^2}=9604  

And rounded we have that n=9604

6 0
3 years ago
(15 points) + (brainliest)
LiRa [457]
Im pretty sure it would be product
7 0
4 years ago
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