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Fantom [35]
2 years ago
7

Margo can purchase tile at a store for $0.59 per tile and rent a tile saw for $49. At another store she can borrow the tile saw

for free if she buys tiles there for $1.29 per tile. How many tiles must she buy for the cost to be the same at both stores?
Margo must buy
tiles for the cost to be the same at both stores.
Mathematics
1 answer:
katovenus [111]2 years ago
7 0

Answer:

Also need help

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What is the GCF of 28ab and 42b?<br> 6b<br> 14b<br> 4b<br> 7b<br> NEED ASAP
grigory [225]

Answer:

14b

Step-by-step explanation:

Here, we want to get the greatest common factor of the two terms

The greatest common factor can be obtained by finding the expression that factor the given expression

We have this as;

14b(2a + 3)

So the greatest common factor is 14b

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3 years ago
4 cups of pineapple juice, 8 cups of orange juice and 12 cups of Sprite makes 18 servings. How many cups of pineapple juice will
Ronch [10]

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24 cups.

Step-by-step explanation:

18 serving requires 4 cups of Pine apple

for 108 serving, 108/18 = 6 times.

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2 years ago
6. If the net investment function is given by
Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated  capital for the period.

  • (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

  • (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

I(t) = 100 \cdot e^{0.1 \cdot t}

(a) The capital formation is given as follows;

\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot  e^{0.1 \cdot t}} + C

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore,  for the three years; Year 3, year 4, and year 5, we have;

\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

\displaystyle  \mathbf{\left[1000 \cdot  e^{0.1 \cdot t}} + C \right]^t_0} = 100,000

Which gives;

\displaystyle 1000 \cdot  e^{0.1 \cdot t}} - 1000 = 100,000

\displaystyle \mathbf{1000 \cdot  e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000

\displaystyle e^{0.1 \cdot t}} = 101

\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

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2 years ago
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Answer:

16x+12

Step-by-step explanation:

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