Answer:
1. Speed=0
2. 2.46 s
3.30.1 m
4. 22.0 m
5.1.004 s
Explanation:
We are given that
Initial speed of blue ball, u=24.1 m/s
Height of blue ball from ground y_0=0.5 m
Initial speed of red ball , u'=7.2 m/s
Height of red from ground=y'0=32 m
Gravity, g=
1.When the ball reaches its maximum height then the speed of the blue ball is zero.
2.v=0

Using the formula and substitute the values

Where g is negative because motion of ball is against gravity


3.
Using the formula


4.Time of flight for red ball=3.77-2.9=0.87s


Hence, the height of red ball 3.77 s after the blue ball is 22.0 m.
5.According to question






Hence, 1.004 s after the blue ball is thrown are the two balls in the air at the same height.
Explanation:
1 mile = 1609m
Distance=260 miles= 418340 m
Speed= 40 m/s
Time = distance/speed
= 418340/40
=10458.5 seconds
= 2.9 hours
It’s North of the equator
Answer:
Explanation:
Given that
Beam current (i)=23.3µA
And the time to strike(t)=28s
Also, a fundamental charge e=1.602×10^-19C
Then, the charge quantity is given as,
q=it
Then, q=23.3×10^-6×28
q=6.524×10^-4C
Also, the number of electron N is given as
q=Ne
Therefore, N=q/e
So, N=6.524×10-4/1.602×10^-19
N=4.072×10^15
There are 4.072×10^15 electrons strike the tube screen every 28 s.
Answer:
hope
that helps
Explanation:
D. The sleeper's heart rate, blood pressure, and breathing rate drop to their lowest levels.