In a force diagram set-up, we name the angle of inclination theta, g as the acceleration due to gravity. In this case, the forces acting on the box going down is the weight itself impeded by the friction between the box and the inclined plane.
The weight of the box is expressed as mg sin theta
The frictional force is expressed as the normal force times the coefficient of friction that is expressed as mu g cos theta.
By Newton's second law of motion, F = ma = mg sin theta - mu g cos theta
Thus, a = g (sin theta - u cos theta
Answer:
I'm pretty sure it'sssss A
I believe the answer is A
Answer:
Explanation:
Given that,
Current in wire is
I = 10A
And the current makes an angle of 30° with respect to the magnetic field
Then, θ = 30°
And the magnetic field is
B = 0.3 T
Length of the wire is
L = 0.5m
Force on the wire F?
The force on the wire in calculated using
F = iL × B
Where
The magnitude of the cross produce of L and B is
L × B = LB•Sinθ
Then, force becomes
F = iLB•Sinθ
F = 10 × 0.5 × 0.3 × Sin30
F = 0.75 N
The force on the wire is 0.75 Newton