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Firdavs [7]
3 years ago
15

How many times Father is Proxima Centauri from the sun then is earth from the sun answer choices about 269,000 times or about 0.

0000037 times or about 0.00269 times were about 26.9 times
Physics
1 answer:
Bas_tet [7]3 years ago
4 0

Answer:

269,000

Explanation:

The distance between Proxima Centauri and the Sun, d₁₁ = 4.246 light years

The distance between Earth and the Sun, d₂ = 1.58 × 10⁻⁵ light years

The ratio of the distances are;

d₁/d₂ = 4.246/(1.58 × 10⁻⁵) = 268734.177215 ≈ 269,000 times

Therefore, Proxima Centauri is approximately 269,000 times further from the Sun than the Earth is from the Sun

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What is the total resistance of the circuit shown above?​
stepladder [879]

Answer:

6.67

Explanation:

7 0
2 years ago
Bowling balls are roughly the same size, but come in a variety of weights. Given its official radius of roughly 0.110 m, calcula
velikii [3]

Answer:

6.1328 kg

60.16284 N

Explanation:

r = Radius of ball = 0.11 m

\rho = Density of fluid = 1.1\times 10^3\ kg/m^3 (Assumed)

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of ball

V = Volume of ball = \frac{4}{3}\pi r^3

The weight of the bowling ball will balance the buouyant force

W=F_b\\\Rightarrow mg=V\rho g\\\Rightarrow m=\frac{V\rho g}{g}\\\Rightarrow m=V\rho\\\Rightarrow m=\frac{4}{3}\pi 0.11^3\times 1.1\times 10^3\\\Rightarrow m=6.1328\ kg

The mass of the bowling ball will be 6.1328 kg

Weight will be 6.1328\times 9.81=60.16284\ N

5 0
3 years ago
Hello can someone please help me with this.
user100 [1]

Answer:

They are not concerned about their future health cause they are thinking they are probably healthy right now and they don’t realize that that can change in the future. If u are fit right now then that means u wont struggle with future physical fitness activities.

Explanation:

8 0
3 years ago
Suppose that a public address system emits sound uniformly in all directions and that there are no reflections . The intensity a
Marina86 [1]

Answer:

I_{2}=2.39*10^{-5} W/m^{2}

Explanation:

The definition of the intensity in terms of power is given by:

I=\frac{P}{A}

Where:

  • P is the power
  • A is the area

If the sound emits uniformly in all directions and that there are no reflections, we can assume the geometry of the wave sound is spherical.

Let's recall the area of a sphere is A = 4\pi R^{2}

To the first location we have:

I_{1}=3*10^{-4} W/m^{2}=\frac{P}{4\pi 22^{2}}

and to the second location we have:

I_{2}=\frac{P}{4\pi 78^{2}}

Now, we can divide each intensity to find the second intensity.

\frac{I_{2}}{I_{1}}=\frac{\frac{P}{4\pi 78^{2}}}{\frac{P}{4\pi 22^{2}}}

I_{2}=I_{1}* \frac{22^{2}}{78^{2}}

I_{2}=3*10^{-4}\frac{22^{2}}{78^{2}}

I_{2}=2.39*10^{-5} W/m^{2}

I hope it helps you!

     

5 0
3 years ago
Read 2 more answers
1) how does reflection differ from diffraction?
Evgesh-ka [11]

Answer: (1) The correct answer is A.

(2) The correct answer is D.

Explanation:

(1)

Reflection is the sending back of light from the surface without absorbing it. In the reflection phenomenon, the wave does not continue moving forward.

Diffraction is the bending of the light around the obstacle. In the diffraction phenomenon, the wave travels forward after striking around the obstacle.

Therefore, the correct answer is A.

(2)

Amplitude is the maximum displacement in the medium from the rest position.

The amount of energy is related to the amplitude. Amplitude is related to the amount of energy carried by the wave. Low energy wave is characterized by a low amplitude. High energy wave is characterized by a high amplitude.

Therefore, the correct option is D.

5 0
3 years ago
Read 2 more answers
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