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Select the correct answer.

V125BC [204]

Answer:

b

Step-by-step explanation:

any set times the radius will give you the answer

3 0

3 years ago

Which expression is equivalent to x2 - 8x + 15

Valentin [98]

The answer is ( x - 3 ) ( x - 5)

3 0

3 years ago

Four members from a 45-person committee are to be selected randomly to serve as chairperson, vice-chairperson, secretary, and

wariber [46]

Answer:

3575880

Step-by-step explanation:

We need to use Permutation method,

$nPr= \frac{n!}{(n-r)!}$

Where n is the sample of size and r the combination considered, so

$n=45\\r=4\\45P4= \frac{45!}{(45-4)!}\\45P4 = 3575880$

There is 3575880 possibilities to make leadership structures in that committee

6 0

3 years ago

2.5(t - 2) - 6 = 9 (solve for the unknown variable)

Elis [28]

2.5(t - 2) - 6 = 9

2.5(t - 2) = 9 + 6 = 15

t - 2 = 15/2.5 = 150/25 = 6

t = 6 + 2 = 8

Answer: 8

Check: 2.5(8 - 2) - 6 = 2.5(6) - 6 = 1.5(6) = 9 good

3 0

3 years ago

The Martinez family went to the movies and paid $60 for two adult tickets and three children’s tickets. The Wright family consis

Pepsi [2]

Answer:

a = $13.5

Step-by-step explanation:

Let a = adult tickets

Let c = children tickets

Translating the word problem into an algebraic equation;

For the Martinez family;

2a + 3c = $60

For the Wright family;

3a + 5c = $95.5

Thus, the simultaneous equations are;

$2a + 3c = $60$ ..........equation 1

$3a + 5c = $95.5$ .........equation 2

We would use substitution method to solve;

From equation 2, we make a the subject of formula;

3a = 95.5 - 5c

a = (95.5 - 5c)/3

Substituting the value of "a" into equation 1, we have;

2[(95.5-5c)/3] + 3c = 60

Multiplying all through by 3;

2(95.5 - 5c) + 9c = 180

191 - 10c + 9c = 180

191 - c = 180

c = 191-180

c = $11

To find the value of a;

2a +3c = 60

Substituting the value of "c" into the equation, we have;

$2a + 3(11) = 60$

$2a + 33 = 60$

$2a = 60 - 33$

$2a = 27$

$a = \frac{27}{2}$

a = $13.5

Therefore, the cost of an adult movie ticket is $13.5.

5 0

2 years ago

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