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andrew11 [14]
3 years ago
5

Adrian is using an indirect method to prove that segment DE is not parallel to segment BC in the triangle ABC shown below:

Mathematics
1 answer:
VikaD [51]3 years ago
4 0
If we start with the assumption that segment DE is parallel to segment BC, then we the similarity condition that:
triangle ABC is similar to triangle ADE
For this to be true, the ratio corresponding sides of the two triangles must be equal. So:
5/8 =? 6/10
But
5/8 =/= 6/10

So, DE is not parallel to BC
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Answer:

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3 years ago
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Answer:

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