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SpyIntel [72]
2 years ago
6

Find the 19th term in each sequence. 11, 33, 99, 279

Mathematics
1 answer:
Paladinen [302]2 years ago
8 0

Answer:

Step-by-step explanation:

hello : note 297 no 279

297 =3×99

99 = 3 ×33

33=3×11

this the geometric sequence. ( comon : 3)

the nth term is : An = A1 × r^n     when : r = 3 and A1 =11

if n = 19      A19 = 11×3^19

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Which value from the set {2, 3, 6, 7} makes 3x + 5 = 11 true?
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Answer:

2

Step-by-step explanation:

3 x 2 = 6 + 5 = 11

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There are 15 candidates for 4 job positions.
Veronika [31]

Answer:

32760 ways

Step-by-step explanation:

Given

Number of Candidates = 15

Job Positions = 4

Required:

Number of outcomes

This question represent selection; i.e. selecting candidates for job positions;

This question can be solved in any of the following two ways

Method 1.

The first candidate can be chosen from any of the 15 candidates

The second candidate can be chosen from any of the remaining 14 candidates

The third candidate can be chosen from any of the remaining 13 candidates

The fourth candidate can be chosen from any of the remaining 12 candidates

Total Possible Selection = 15 * 14 * 13 * 12

<em>Total Possible Selection = 32760 ways</em>

<em></em>

Method 2:

This can be solved using permutation method which goes thus;

nPr = \frac{n!}{(n-r)!}

Where n = 15 and r = 4

So;

nPr = \frac{n!}{(n-r)!} becomes

15P4 = \frac{15!}{(15-4)!}

15P4 = \frac{15!}{11!}

15P4 = \frac{15*14*13*12*11!}{11!}

15P4 = 15*14*13*12

15C4 = 32760

<em>Hence, there are 32760 ways</em>

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How many decimeters are there if there are 3 centimeters.
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