First we need to find the slope
y2-y1/x2-x1
-6-4/-3-2
-10/-5 <---this can be simplified
Slope=2
Point slope:
y-y1=m(x-x1)
Now take the first pair of coordinates and plug them in their proper spots it helps to label them then plug in
y1=4
x1=2
m=slope=2
Now plug them in our final answer would be :
y-4=2(x-2)
Slope intercept:
<span>y = mx + b
</span><span>where:
m is the slope of the line
b is the y-intercept of the line
Slope is known
y=2x+b
To find the b you pick one of the given coordinates let's do (2,4)
Plug them into what we have
y=2x+b
4=2(2)+b
solve for b
4=4+b
subtract 4 from both sides
b=0 therefore the equation would simply be
y=2x</span>
Answer:
m∠ADC = 90°
5x-5 = 90
x = 19
Step-by-step explanation:
Answer to the first question is A. X = 10 and y = -2. Plug it into the equation.
-2 + 2 = 3/5(10 - 10)
0 = 0
Answer to the second question is A. It is going up "rise" by 4. And left "run" by -5
Answer to the third question is A. 2x will represent the slope. 5 will represent the y intercept.
Answer to the fourth question is C.
Answer to the last question is B. y = 5(1) y = 5. y = 5(0) y = 0.
Hope that helps
R=d/2
R=40/2
R=20
A=πr^2
A=π20^2
A=π400
A=1256.637061
Area of triangle=(b*h) /2
A=(40*20)/2
A=800/2
A=400
Area of circle-area of triangle=area of shaded region
1256.637061-400=856.637061
Hope this helps!
Answer:
<u>The correct answer is D. 15 squared centimeters.</u>
Step-by-step explanation:
1. Let's review the data given to us for solving the question:
Base one = 10 centimeters
Base two = 5 centimeters
Height = 2 centimeters
2. Let's find out the area of the trapezoid, using the following formula:
Area = 1/2 (Base one + Base two) * Height
Replacing with real values:
Area = 1/2 (10 + 5) * 2
Area = 1/2 (15 * 2) = 1/2 (30)
Area = 15 centimeters ²
<u>The correct answer is D. 15 squared centimeters.</u>
Note: Same answer provided to question 14021584, answered by me.
