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3 years ago

8,-67, -99, -91, -59, -81, 46 find the average of the following set of integers

Mathematics

1 answer:

konstantin123 [22]3 years ago

7 0

Answer:

The average is -49.

Step-by-step explanation:

You add all numbers and then divide by the numbers that your adding:

8+-67+-99+-91+-59+-81+46= -252

-252/7= -49

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Question 9 - (3 marks available)

finlep [7]

Answer: a) 1,600

b) 35,000

c) 120,000

Step-by-step explanation:

First, round each number to one significant digit (the first digit).

Then multiply them.

a) 17 --> rounds to 20

82 --> rounds to 80

20 x 80 = 2 x 8 with two zeros

= 1 6 0 0

b) 54 --> rounds to 50

671 --> rounds to 700

50 x 700 = 5 x 7 with three zeros

= 3 5 0 0 0

c) 207 --> rounds to 200

643 --> rounds to 600

200 x 600 = 2 x 6 with four zeros

= 1 2 0 0 0 0

6 0

3 years ago

Please enter the missing number: 2, 9, 20, 37, 64, 107, ?

k0ka [10]

174 is the missing number

4 0

3 years ago

4x^2-24x+4y^2+72y=76

podryga [215]

Simplifying 4x2 + -24x + 4y2 + 72y = 76
Reorder the terms: -24x + 4x2 + 72y + 4y2 = 76
Solving -24x + 4x2 + 72y + 4y2 = 76
Solving for variable 'x'.
Reorder the terms: -76 + -24x + 4x2 + 72y + 4y2 = 76 + -76
Combine like terms: 76 + -76 = 0 -76 + -24x + 4x2 + 72y + 4y2 = 0
Factor out the Greatest Common Factor (GCF), '4'. 4(-19 + -6x + x2 + 18y + y2) = 0
Ignore the factor 4.

Subproblem 1
Set the factor '(-19 + -6x + x2 + 18y + y2)' equal to zero and attempt to solve: Simplifying -19 + -6x + x2 + 18y + y2 = 0 Solving -19 + -6x + x2 + 18y + y2 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.
The solution to this equation could not be determined.

7 0

3 years ago

Find the quotient. (2x^4-3x^3-6x^2+11x+8)/(x-2)

stiv31 [10]

Since the remander is 0 the answer is 2x²+5x+2

4 0

3 years ago

Read 2 more answers

A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)

Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

$36^6$

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

$5\cdot 36^5$

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

$\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}$

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

$P(A)=P(B)=\dfrac{5}{36}$

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

$axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8$