1. (t-5)^2+3=t^2-10t+12+3=t^2-10t+15.
2. (a+h)^2+3=a^2+2ah+h^2+3
(a^2)+3=a^2+3. Subtracting, we get h^2+2ah.
3. (a^2)+3=a^2+3
(a-h)^2+3=a^2-2ah+h^2+3. Subtracting, we get 2ah-h^2.
Answer:
15 cm
Step-by-step explanation:
Circumference of circle= 2πr, where r us the radius of the circle.
Given that the circumference of circle is 60πcm,
60π= 2πr
Divide by 2 on both sides,
15π= πr
Divide by π on both sides,
15= r
Thus, radius of circle= 15cm.
Since the x values cancel out and we are left with 6=6, all x values will work for x because it will dissapear anyway
with some modification, we can get x=x, so therefor that is true and all values work
C is answer
Answer:
2( 4 + 2X) = 3x + 4
8 + 4x = 3x + 4
8 + 4x - 3x - 4 = 0
x + 4 = 0
x = -4
Step-by-step explanation:
The answer would be 4.6 x 10^-5
