The answer is b y=6 Use photonath if any more equations like this one
Considering that the addresses of memory locations are specified in hexadecimal.
a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations
b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095
<u>applying the given data </u>:
a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )
( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )
= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )
= 61440 + 3840 + 240 + 15 = 65535
∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations
b) The range of hex addresses with a memory location of 4096
= 0000₁₆ to FFFF₁₆ = 0 to 4096
∴ the range = 4095
Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.
Learn more : brainly.com/question/18993173
Answer:
Step-by-step explanation:
the quotient of is the result of dividing two terms
The first term is - Twice a number t: 2t
The second term is - and 12: 12 2t÷12or 2t12
Answer:
=5x^2y+15
Step-by-step explanation:
16x^0+5x^2*y-1=
16x0+5x2y−1
Combine Like Terms:
16+5x2y+−1
=(5x2y)+(16+−1)
=5x^2y+15
Hope this helps!!! If you ever need more help just ask in the comments or somewhere.
I’m pretty sure it’s D
If not mb .......
