The answer would be 938.62.
Answer: the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
Step-by-step explanation:
Given data;
lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min
hence, height = 1 / ( 52.0 - 50.0) = 1 / 2
now the probability that the class length is between 50.8 and 51 min = ?
P( 50.8 < X < 51 ) = base × height
= ( 51 - 50.8) × 1/2
= 0.2 × 0.5
= 0.1 ≈ 10%
therefore the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
Answer:
a is the hypotenuse, b is adjacent, c is opposite
Step-by-step explanation:
Answer:
the answer is d.the statement is always true
Step-by-step explanation:
take x as odd integer
So,
x+2=1+2=3
x+6=3+6=9
Answer:
So, the relation between variables are
![y=\frac{x^4}{7}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bx%5E4%7D%7B7%7D)
Step-by-step explanation:
We are given
![\frac{x^4}{y}=7](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E4%7D%7By%7D%3D7)
Since, we have to find relation between variables
so, we can solve for y
![\frac{x^4}{y}=7](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E4%7D%7By%7D%3D7)
Firstly, we will multiply both sides by y
![\frac{x^4}{y}\times y=7\times y](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E4%7D%7By%7D%5Ctimes%20y%3D7%5Ctimes%20y)
we can simplify it
![x^4=7\times y](https://tex.z-dn.net/?f=x%5E4%3D7%5Ctimes%20y)
we can isolate y
so, we can divide both sides by 7
so, we get
![y=\frac{x^4}{7}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bx%5E4%7D%7B7%7D)