If other tickmarks are labeled, then you could do some detective work (of sorts) to figure out the unlabeled tickmarks.
For example, let's say we had a number line with 1,2,3,... and let's say that 7 was covered up or erased or smudged. So we have 1,2,3,4,5,6,__,8,9. We could then easily determine that 7 must go in that blank spot. This is just one example of course.
Another example could be that if we had a tickmark right in the middle of two whole numbers, say 0 and 1. This unlabeled tickmark would most likely be 1/2 = 0.5 as its at the halfway point between 0 and 1.
Answer:
a=1/2
Step-by-step explanation:
Answer:
The answer to your question is A = 200.96 u²
Step-by-step explanation:
Data
Radius A = 6
Radius B = 2
π = 3.14
Area = ?
Formula
Area = πr²
Process
1.- Calculate the radius of the large circle
Radius = radius of circle A + radius of circle B
Radius = 6 + 2
Radius = 8
2.- Substitute in the formula
Area = (3.14)(8)²
Area = 3.14(64)
Area = 200.96 u²
Answer:
Thanks you
Step-by-step explanation:
For this case we have that by definition, a direct variation is given in the form:
Where:
k: It is the constant of proportionality
According to the statement we have to:
Substituting:
On the other hand we have:
Answer:
