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Leya [2.2K]
2 years ago
9

Help picture below problem 9

Mathematics
2 answers:
Agata [3.3K]2 years ago
7 0

Answer:

i think the answer might be E.

hammer [34]2 years ago
4 0

the answer is A option that is <em><u>Angle M</u></em>

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Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

  • MO/Shortest MO/Medium and MO/Longest

a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

The next shortest side is the side opposite ∠M(61°) = \frac{}{NO}

The longest side is the side opposite ∠O(65°) = \frac{}{MN}

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

The mean number of minutes spent on aerobic training is found as follows;

Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

Learn more here:

brainly.com/question/2962546

4 0
2 years ago
What is the slope of the line that passes through
den301095 [7]

Answer:

what does it pass through

7 0
2 years ago
Fill in the correct justification for each step in solving the equation below 3(12-9x)=-16x+58
BaLLatris [955]

<u>answer:</u>

given

distributive property

subtraction property of equality

addition property of equality

division property of equality

hope this helps! :)❤ from peachimin



4 0
3 years ago
PLEASE HELPPP! ILL GIVE 50 POINTS ACTUALLY PUT THE ANSWER PLEASE ..
frosja888 [35]

Answer:

how do i know you are not point scammer?????

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A software company is releasing one of their products on a CD. The manufacturer charges a $5,500 setup fee and $1.00 per CD. App
olga_2 [115]
Setup Fee= $5,500Per CD Charge= $1.00Desired Cost Per CD= $3.50
x= number of CDs

Desired Cost Per CD= Cost per CD + Setup Fee
($3.50 * x)= ($1.00 * x) + $5,500multiply inside parentheses
$3.50x= $1.00x + $5,500subtract $1.00x from both sides
$2.50x= $5,500divide both sides by $2.50
x= 2,200 CDs

ANSWER: x= 2,200 CDs
Hope this helps!  :)



4 0
3 years ago
Read 2 more answers
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