Answer:
Step-by-step explanation:
edge 2020
Picking digits from the list 1, 2, 3, 4, 5, 6, 7, 8, 9 just once, we build two four-digit natural numbers in such a way that the
1 answer:
Answer:
3825
Step-by-step explanation:
Given that we have to pick digits from the list 1, 2, 3, 4, 5, 6, 7, 8, 9 just once and build 4 digit numbers.
Find the two numbers which have the sums as the smallest
Since when the two numbers formed are the smallest the sum will be the smallest, we can pick digits in such a ways that the numbers have value the smallest. If the 1000th digit is small we would get smaller number. So let us take for first digit 1000th place 1 and second number 1000th place as 2.
Similarly for 100th now available are 3,4...8, 9 so let us take 100th digit as 3 and 5 respectively and so on.
So the numbers would be
1357 and 2468
Sum would be
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Answer:
1. Domain (-∞, ∞)
Range: (-20, ∞)
x-intercepts: (-5, 0), and (5, 0)
y-intercepts: (0, -25)
Interval positive: (-∞, -5), and (5, ∞)
Interval negative: (-5, 5)
Interval increasing: (0, ∞)
Interval decreasing: (-∞, 0)
Given that the shape is that of a quadratic graph, we have;
f(x) = (x - 5)×(x + 5) = x² - 25 = 0
Where;
The 5s are from the x-intercept
The slope = dy/dx = d(x² - 25)dx = 2·x
The slope at the point (-2, 0), therefore, x is -2, we have;
Slope = 2·x = 2 × x = 2 × (-2) = -4
The slope at the point (-2, 0) = -4
The rate of change over the interval = (-20 - (-25))/(-2 - 0) = -2.5
The rate of change over the interval = -2.5
2) Domain (-∞, ∞)
Range: (3, ∞)
x-intercepts: N/A
y-intercepts: (0, 7)
Interval positive: (-∞, ∞)
Interval negative: NA
Interval increasing: (-2, ∞)
Interval decreasing: (-∞, -2)
Given that the shape at (-2, 0) is that of a straight line graph, we have;
Rate of change = dy/dx = (7 - 3)/(0 - (-2)) = 2
The rate of change over the interval (-2, 0) = 2
3) Please find attached, the required graph drawn using Microsoft Excel
4) The key features are;
Domain: (0, 50/0.5) = (0, 100)
Range: (0, 50)
x-intercepts: (0, 0)
y-intercepts: (0, 0)
Interval positive: (0, 100)
Interval negative: N/A
Interval increasing: (0, 100)
Interval decreasing: N/A
The rate of change over the interval (-2, 0) = 0.5 ft³/min
Step-by-step explanation:
The domain is the range of values of the input (x) variables
The range is the range of values of the output (y) variables
The x-intercepts. are the points where the graph crosses the x-axis
The y-intercepts. are the points where the graph crosses the y-axis
The interval positive is the range of values over which the y-values are larger than 0
The interval negative is the range of values over which the y-values are lesser than 0
The interval increasing is the range of values over which the y-values are continuously increasing
The interval decreasing is the range of values over which the y-values are continuously decreasing
The rate of change over an interval is the ratio of the change in the y-values to the corresponding change in the x-values, over the range.
