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2 years ago

14

At andres birthday party 3 pizzas were ordered for lunch. Each pizza was divided into 8 equal slices. Each child ate 2 pieces an

d there were 2 pieces left how many children were at the party?

2 answers:

vodka [1.7K]2 years ago

7 0

Answer:

11

Step-by-step explanation:

So each pizza has 8 equal slices but we don't know the amount pizzas but we can find it by doing this ⬇️

1 pizza= 8 slices

3 pizzas = x

you cross multiply it and it will end up as 3×8= 24 slices.

now each kid ate 2 pieces and there was a leftover of 2

therefore, 24-2= 22 pieces divided 2 is 11

or; 3×8=24-2=22÷2=11

pogonyaev2 years ago

4 0

Answer: I dont know if im right for sure but the answer should be 4

Step-by-step explanation

8 goes into 2 4 times (8 divided by 2 = 4)

Each child ate 2 pieces (4-2=2)

so therefore for it to be 2 pieces left over there were 4 kids I think.

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Whats up wate is 3000+39645

kozerog [31]

Answer:

MARK ME BRAINLIEST BRO!!!!!!!!

Step-by-step explanation:

5 0

3 years ago

What is the answer to the question down below

ratelena [41]

We conclude that the measure of that angle is 150 degrees.

<h3>How to get the measure of angle BFE?</h3>

Notice that the measure of angle ∠BFE will be equal to:

∠BFE = ∠BFC + ∠CFD + ∠DFE

Where:

∠CFD = 90°

∠DFE = 30°

And we will have that:

∠AFC = 180° - 90° - 30° = 60°

And we know that BF bisects that angle, then:

∠BFC = 30°

So we conclude that:

∠BFE = ∠BFC + ∠CFD + ∠DFE = 30° + 90° + 30° = 150°

We conclude that the measure of that angle is 150 degrees.

If you want to learn more about angles:

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5 0

2 years ago

Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given freque

maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals Frequency

100 - 199 24

200 - 299 90

300 - 399 27

400 - 499 1

500 - 599 4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

99.5 - 199.5

199.5 - 299.5

299.5 - 399.5

399.5 - 499.5

499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

$\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{99.5+199.5}{2}\\\\=149.5$

$\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{199.5+299.5}{2}\\\\=249.5$

$\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{299.5+399.5}{2}\\\\=349.5$

$\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{399.5+499.5}{2}\\\\=449.5$

$\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{499.5+599.5}{2}\\\\=549.5$

The number of individuals included in the summary is the sum of all frequencies.

$\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146$

Thus, the number of individuals included in the summary is 146.

3 0

3 years ago

Read 2 more answers

Show all work to solve by factoring 3x^2 − x − 2 = 0.

shtirl [24]

Answer:

The solutions are x=1 and x=-2/3

Step-by-step explanation:

we have

$3x^{2}-x-2=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$3x^{2}-x=2$

Factor the leading coefficient

$3(x^{2}-(1/3)x)=2$

Complete the square. Remember to balance the equation by adding the same constants to each side

$3(x^{2}-(1/3)x+(1/36))=2+(1/12)$

$3(x^{2}-(1/3)x+(1/36))=25/12$

Rewrite as perfect squares

$3(x-(1/6))^{2}=25/12$

$(x-(1/6))^{2}=25/36$

square root both sides

$(x-(1/6))=(+/-)(5/6)$

$x=(1/6)(+/-)(5/6)$

$x=(1/6)(+)(5/6)=1$

$x=(1/6)(-)(5/6)=-2/3$

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3 years ago

Help ?? Anyone and how

ELEN [110]

Answer:

just insert the x numbers in the calculation.. so for x = - 3 - > (- 3) / 2 +4 = 2.5

Step-by-step explanation:

x - 2 = y 3

and so on

7 0

3 years ago