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mrs_skeptik [129]
3 years ago
15

Can somebody pls help me with this question I dont get it

Mathematics
1 answer:
alekssr [168]3 years ago
6 0

Answer:

1. 195=6.50·c

2. 30

Step-by-step explanation:

195=6.5·c

Divide both sides by 6.5

30=c

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What is the benefit of dividing out greatest common factors (GCFs) before multiplying?
Nina [5.8K]
Lets get an example, for this example lets use 24/30 x 30/60
Without dividing out GCFs  you would get 24x12 over 30 x 60 which is 288/1800
With dividing out GCFs you get 2/1 x 5/1 Which is 7 :)
7 0
3 years ago
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What is the side length a in the triangle below?
grigory [225]

Answer:

a=5

Step-by-step explanation:

a^2+b^2=c^2

c^2-b^2=a^2

13^2-12^2=a^2

169-144=a^2

25=a^2

5=a

8 0
2 years ago
PLEASE HELP Im DESPERATE ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!
iren [92.7K]

Put 40y and 25.5

Step-by-step explanation:

I js did it lol

7 0
2 years ago
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
How to scientific notation to express the number 480 into 1 scientific notaion?
AfilCa [17]

Consider the number 480 in expanded form:

... 480 = 4×100 + 8×10

The left-most digit and multiplier are those that correspond to the ones you use in scientific notation.. You recall that 100 = 10×10 = 10². All this means is that

... 480 = 4.8×10²

5 0
3 years ago
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