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AnnZ [28]
2 years ago
7

Determine if the two figures are congruent and explain your answer using transformations

Mathematics
1 answer:
nignag [31]2 years ago
8 0

Answer:

Step-by-step explanation:

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Which question could be answered by the organized list shown? Select two answers.
umka2103 [35]

Answer:

A and E

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
the denominator of a fraction is 3 less than the numerator. If 5 is added to the numerator and denominator, the result is 5/6. F
Vitek1552 [10]
X=numerator
y=denominator
the sum of numerator and denominator=x+y
we suggest this system of equations:

y=x-3
(x+5) / (y+5)=5/6

we solve this system of equation by substitution method.
(x+5) / (x-3+5)=5/6
(x+5) / (x+2)=5/6
6(x+5)=5(x+2)
6x+30=5x+10
6x-5x=10-30
x=-20

y=x-3=-20-3=-23

Teh sum of the numerator an denominator=-20+(-23)=-43

Answer:    -43



7 0
3 years ago
Addmaths probability. I need helpp for question a and b thank youu
motikmotik

Answer:

sorry this is soo blur

please follow me and mark has brilliant please

7 0
2 years ago
3s+2t−3 =c<br> −7s−5t =4<br> ​
irinina [24]

Answer:

c=

−4

3

s−t+

−4

3

Step-by-step explanation:

Let's solve for c.

3s+2t−3c−7s−5t=4

Step 1: Add 4s to both sides.

−3c−4s−3t+4s=4+4s

−3c−3t=4s+4

Step 2: Add 3t to both sides.

−3c−3t+3t=4s+4+3t

−3c=4s+3t+4

Step 3: Divide both sides by -3.

−3c

−3

=

4s+3t+4

−3

c=

−4

3

s−t+

−4

3

3 0
3 years ago
A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
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