Question

!!!!!GIVING BRAINLIEST!!!!!

Answer 1

Answer:

Given equation,

3|x| > 6 -----(1)

∵ $\frac{1}{3}>0$

Thus, multiplying both sides of inequality (1) by $\frac{1}{3}$

We get,

$|x| > 2$

⇒ 2 < x or 2 < - x  

⇒ 2 < x or -2 > x   (when a > b where a > 0, b > 0, If c < 0  ⇒ ac < bc),

⇒ (2, ∞ ) ∪ (-∞, -2)

By plotting the above interval in the number line we can get the graph of the given equation ( shown below )

Answer 2

Shown below is the graph on the x-y plane.

Your equation has only one variable, so a graph on the number line is appropriate. It would extend outward from ±2, where the points would be indicated by open circles.