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2 years ago

I need help please!!! thank you so much to the person who is going to help me.

Mathematics

2 answers:

ollegr [7]2 years ago

6 0

X = y * 1.07

X = cost after tax
y = item before tax added

Ray Of Light [21]2 years ago

6 0

The answer is 1.07 your welcome dear

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Solve<br> 2X-3(x+4)=3x-4

Phoenix [80]

Answer: x=4

Step-by-step explanation:

2x-3(x+4)=3x-4

distribute 2x-3x-12=3x-4

combine like terms 5x-12=3x-4

Move everything to one side 2x-8=0

Get x by itself 2x=8

Divide by 2 x=4

6 0

3 years ago

Which of the following is a linear function?

Rama09 [41]

$\boxed{ \textbf{ \huge{Answer: A}}}$

A linear function has 1 as the highest power of the variable.

A. f(x) = 2 - 7x

here, the highest power of the variable x is 1.
Hence it is a LINEAR function.
___________

B. f(x) = 2 + x + x^2

here, the highest power of the variable x is 2.
Hence it is NOT a linear function.
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$c.f(x) = \sqrt{2 + 7x}$
here, the highest power of the variable x is 1/2.
Hence it is NOT a linear function.
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6 0

3 years ago

A cube with side length 5h^2 is stacked on another cube with side length 3k What is the total volume of the cubes in factored fo

dalvyx [7]

<span>Just find the volume of each cube separately and add together the results. First cube has side length 5h^2. What is the formula for the volume of a cube? Second cube has side length 3k. Whats its volume?</span>

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3 years ago

Read 2 more answers

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$