A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 20 is about 4.472. Thus, the square root of 20 is not an integer, and therefore 20 is not a square number.
3 9/100 would be written as a decimal like this, 3.09. You say three and nine one hundredths. The 9 has to be in the hundredths place, so you put a 0 in front of it. And since the 3 is hole, you put it in front of the decimal point.
Answer:
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Step-by-step explanation:
Simplify the following polynomial expression:
(5x^4 - 9x^3 + 7x -1) + ( -8x^4 + 4x^2 - 3x + 2) - ( -4x^3 + 5x -1) (2x - 7)
Lets Simplify Your Equation, Step by Step:
(5x^4 - 9x^3 + 7x -1) + ( -8x^4 + 4x^2 - 3x + 2) - ( -4x^3 + 5x -1) (2x - 7)
Solution: ===> 5x^4 − 37x^3 − 6x^2 + 41x − 6 = 0
Distribute:
= 5x^4 + -9x^3 +7x + −1 + −8x^4 + 4x^2 + −3x + 2 + 8x^4 + −28x^3 + −10x^2 + 37x + −7
Combine Like Terms:
= 5x^4 + −9x^3 +7x + −1 + −8x^4 + 4x^2 + −3x + 2 + 8x^4 + −28x^3 + −10x^2 + 37x + −7
= (5x^4 + −8x^4 +8x^4) + (−9x^3 + −28x^3) +(4x^2+ −10x^2) +(7x + −3x + 37x)+(−1 + 2 + −7)
= 5x^4 + −37x^3 + −6x^2 + 41x + − 6
Hence, Answer:
= 5x^4 −37x^3 −6x^2 + 41x − 6 = 0
Hope that helps!!!! : )
