I will give brainliest
1 answer:
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Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!
2 Answers:
Choice C) It will use a closed circle
Choice D) The ray will move to the left
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Explanation:
The inequality means that x = -8 or x < -8. Since we're including -8 itself, which is the endpoint, we'll use a closed circle. In contrast, an open circle would be used if the inequality was
to exclude the endpoint -8.
The ray is to the left because we're visually describing all values smaller than -8. Such example values are -10 and -22 as these values are to the left of -8 on the number line.
In short, the graph consists of a closed circle at the endpoint -8 and the arrow is to the left. We can say the shading is to the left.