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Virty [35]
3 years ago
14

Since the sample size is always smaller than the size of the population, the sample mean a. must be larger than the population m

ean b. can be smaller, larger, or equal to the population mean c. must be equal to the population mean d. must always be smaller than the population mean
Mathematics
1 answer:
Stels [109]3 years ago
7 0

The answer is;

B. Can Be Smaller, Larger, Or Equal To The Population Mean

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How do you find a subtotal
jolli1 [7]

This is the hardest question I've answered all day.

One way to find a sub-total is by *simply* adding everything together, and a example would be below, buy yeah, you just add everything together.

For example:

Cookies (item # 594993) $2.98

Cake (item # 4354533) $4.50

Vans low tops (item # 594939) $60.00

Vans socks (item # 598993) $15.00

And just by adding all this, that how you would find the subtotal. Hope this helps! ;)


5 0
3 years ago
Plz aswer and explain this to me i dont get it
WINSTONCH [101]

Answer: 36

Step-by-step explanation:

1) Find the prime factorization of 12

12=2*2*3

2) Find the prime factorization of 18

18=2*3*3

3) Multiply each factor the greater number of times it occurs in the first two steps above to find the LCM.

LCM=2*2*3*3

4) LCM=36

8 0
3 years ago
Select the correct inequality for the graph below:
Lesechka [4]
 the answer is D. y≤ -2x + 2

take x=2
then (-2 x 2) + 2
⇒ -4 + 2 = -2
4 0
3 years ago
Read 2 more answers
Previously 5% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of
mr Goodwill [35]

Answer:

p value = 0.03514

Step-by-step explanation:

Hypotheses would be

H_0: p = 0.05\\H_a: p

(left tailed test at 10% level of significance)

Here p stands for the sample proportion of mothers smoked more than 21 cigarettes during their pregnancy.

Sample size =130

persons who smoked = 2

Sample proportion = \frac{2}{130} \\=0.0154

Assuming H0 to be true

Std error= \sqrt{0.05*0.95/130} \\=0.01911

p difference = -0.0346

Test statistic z=-1.81

p value = 0.03514

Since p is less than 0.10, significance level, we reject H0

4 0
3 years ago
It is known that diskettes produced by a cer- tain company will be defective with probability .01, independently of each other.
zheka24 [161]

Answer:

1.27%

Step-by-step explanation:

To solve this problem, we may consider a binomial distribution where a customer can either accept or reject (and return) the diskette package.

Lets consider  some aspects:

1. From the formulation of the exercise we know that a package is accepted if it has at most 1 defective diskette. So our event A is defined as:

A = 0 or 1 defective diskette

2. The probability of a diskette being defective is 0.01

3. Each package contains 10 diskettes.

If X is defined as number of defective diskettes in the package, the probability of X is given by a binomial distribution with probability 0.01 and n=10

X ~ Bin(p=0.01, n=10)

Let us remember the calculation of probability for the binomial distribution:

P(X=x)=nCx*p^{x}*(1-p)^{(n-x)} with x = 0, 1, 2, 3,…, n

Where

n: number of independent trials

p: success probability  

x: number of successes in n trials

In our case success means finding a defective diskette, therefore

n=10

p=0.01

And for x we just need 0 or 1 defective diskette to reject the package

Hence,

P(X=x)=10Cx*0.01^{x}*(1-0.01)^{(10-x)} with x = 0, 1

So,

P(A)=P(X=0)+P(X=1)

P(A)=10C0*0.01^{0}*(1-0.01)^{(10-0)} + 10C1*0.01^{1}*(1-0.01)^{(9)}

P(A)=0.99^{10}+10*0.01*0.99^{9}

P(A)=0.9957

Now, because we have 3 packages and we might reject just 1 of them, we can find this probability like this:

3*(1-P(A))*P(A)*P(A) = (1-0.9957)*0.9957*0.9957=0.0127

Finally, we have that the probability of returning exactly one of the three packages is 1.27%

3 0
3 years ago
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