Question

Can someone please prove that the expression (x-y)+(y-z)+(z-x) is equivalent to 0

Answer 1

Answer:

see below

Step-by-step explanation:

$(x-y)+(y-z)+(z-x)\\\\=x-y+y-z+z-x\\\\=(x-x)+(-y+y)+(-z+z)\\\\=0+0+0\\\\=0$