3 years ago

Can someone please prove that the expression (x-y)+(y-z)+(z-x) is equivalent to 0

1 answer:

ELEN [110]3 years ago

5 0

Answer:

see below

Step-by-step explanation:

$(x-y)+(y-z)+(z-x)\\\\=x-y+y-z+z-x\\\\=(x-x)+(-y+y)+(-z+z)\\\\=0+0+0\\\\=0$

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