Neptune's distance from the sun is d₁ = 4.503 x 10⁹ km.
Mercury's distance from the sun is d₂ = 5.791 x 10⁷ km.
Calculate the number of times d₁ is greater than d₂.

Answer: 7.7759 x 10⁻¹ times
Answer:
a= 1 , b = 1/16 , c = 1/256 , d= 3/2 , e=4/9 , f= 16/81
Step-by-step explanation:
The first table is given as;
x 4⁻ˣ
-1 4
0 1
2 1/16
4 1/256
a= 1 , b = 1/16 , c = 1/256
The second table is given as;
x {2/3}^x
-1 3/2
0 1
2 4/9
4 16/81
d= 3/2 , e=4/9 , f= 16/81
The direct distance form A to C is represented by the inequality
AC < 40 yards.
<h3>What is a Triangle ?</h3>
A triangle is a polygon with three sides , three vertices and three angles.
It is given that
Distance form point A to B is 15 yards
Distance form point B to C is 25 yards.
Distance AC = ?
In a Triangle the sum of two sides is always greater than the third side.
Therefore
AC < 15 +25
AC < 40 yards.
Therefore the direct distance form A to C is represented by the inequality AC < 40 yards.
To know more about Triangle
brainly.com/question/2773823
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