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weeeeeb [17]
3 years ago
8

You buy a storage rack that holds 40 CDs you have 27 CDs write an inequalityt that describes how many more cds you can buy and s

till have no more CDs than the rack can hold you buy 15 CDs will they all still fit?
Mathematics
1 answer:
MAVERICK [17]3 years ago
5 0
<span>CD's must be 40 or below, so CD's total≤ 40
 If you already have 27, than 27+(number of CDs bought)</span><span>≤ 40
27+x=40(max)
x=(40-27)
x=13 CDs can be bought, at maximum
so (CDs purchased)</span><span> ≤ 13
Therefore, 15 CDs would be too many to fit in the rack </span>
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Setler79 [48]

Answer:

Therefore values of a and b are

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Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

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where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

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Adding half coefficient of X square on both the side we get

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Therefore,

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Substituting in equation 1 we get

(x-3)^{2}=2

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(x-a)^{2}=b

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a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

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